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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Chứng minh : tan^2 x .( 2cos^2x + sin^2x – 1 ) = sin^2 x

Toán Lớp 9: Chứng minh : tan^2 x .( 2cos^2x + sin^2x – 1 ) = sin^2 x

Comments ( 2 )

  1. \qquad tan^2x(2cos^2x+sin^2x-1)
    =((sinx)/(cosx))^2 [cos^2x+(cos^2x+sin^2x)-1]
    =(sin^2x)/(cos^2x). (cos^2x +1-1)
    =(sin^2x)/(cos^2x). cos^2x
    =sin^2x

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    tan^2(x)(2cos^2(x)+sin^2(x)-1)
    = tan^2(x)(cos^2(x)+cos^2(x)+sin^2(x)-1)
    = tan^2(x)(1+cos^2(x)-1)
    = tan^2(x)cos^2(x)
    = (sin^2(x))/(cos^2(x)) * cos^2(x)
    = (sin^2(x)cos^2(x))/(cos^2(x))
    = sin^2(x)
    -> đpcm 

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222-9+11+12:2*14+14 = ? ( )

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