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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: A = tan^2 alpha * (2cos^2 alpha + sin^2 alpha – 1)

Toán Lớp 9: A = tan^2 alpha * (2cos^2 alpha + sin^2 alpha – 1)

Comments ( 1 )

  1. Giải đáp:
    $A = sin^{2}\alpha$
    Lời giải và giải thích chi tiết:
    ĐKXĐ : $cos\alpha \ne 0$
    Ta có : 
    $A = tan^{2}\alpha . ( 2cos^{2}\alpha + sin^{2}\alpha – 1 )$
    ⇔ $A = \frac{sin^{2}\alpha}{cos^{2}\alpha} . [ cos^{2}\alpha + ( cos^{2}\alpha + sin^{2}\alpha ) – 1 ]$
    ⇔ $A = \frac{sin^{2}\alpha}{cos^{2}\alpha} . ( cos^{2}\alpha + 1 – 1 )$
    ⇔ $A = \frac{sin^{2}\alpha}{cos^{2}\alpha} . cos^{2}\alpha$
    ⇔ $A = sin^{2}\alpha$

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222-9+11+12:2*14+14 = ? ( )