Toán Lớp 9: A= 2√3/√3+√2+√24
B=3^√8- 2^3√-27-1/3^3√125
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Toán Lớp 9: A= 2√3/√3+√2+√24
B=3^√8- 2^3√-27-1/3^3√125
Comments ( 1 )
Giải đáp:
$\begin{array}{l}
A = \dfrac{{2\sqrt 3 }}{{\sqrt 3 + \sqrt 2 }} + \sqrt {24} \\
= \dfrac{{2\sqrt 3 \left( {\sqrt 3 – \sqrt 2 } \right)}}{{\left( {\sqrt 3 + \sqrt 2 } \right)\left( {\sqrt 3 – \sqrt 2 } \right)}} + \sqrt {4.6} \\
= \dfrac{{6 – 2\sqrt 6 }}{{3 – 2}} + 2\sqrt 6 \\
= 6 – 2\sqrt 6 + 2\sqrt 6 \\
= 6
\end{array}$
ý B em ghi lại đề cho rõ ra chứ thế khó hiểu quá