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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 15/căn 6 + 1 + 4/ căn 6 -2 + 12/ căn 6 -3 – căn 6 Tính

Toán Lớp 9: 15/căn 6 + 1 + 4/ căn 6 -2 + 12/ căn 6 -3 – căn 6
Tính

Comments ( 1 )

  1. Giải đáp:
    $M = – 11$
    Lời giải và giải thích chi tiết:
    Ta có : 
    $M = \frac{15}{\sqrt[]{6}+1} + \frac{4}{\sqrt[]{6}-2} + \frac{12}{\sqrt[]{6}-3} – \sqrt[]{6}$
    ⇔ $M = \frac{15(\sqrt[]{6}-1)}{(\sqrt[]{6}+1)(\sqrt[]{6}-1)} + \frac{4(\sqrt[]{6}+2)}{(\sqrt[]{6}-2)(\sqrt[]{6}+2)} + \frac{12(\sqrt[]{6}+3)}{(\sqrt[]{6}+3)(\sqrt[]{6}-3)} – \sqrt[]{6}$
    ⇔ $M = \frac{15(\sqrt[]{6}-1)}{6-1^{2}} + \frac{4(\sqrt[]{6}+2)}{6-2^{2}} + \frac{12(\sqrt[]{6}+3)}{6-3^{2}} – \sqrt[]{6}$
    ⇔ $M = \frac{15(\sqrt[]{6}-1)}{5} + \frac{4(\sqrt[]{6}+2)}{2} + \frac{12(\sqrt[]{6}+3)}{-3} – \sqrt[]{6}$
    ⇔ $M = 3( \sqrt[]{6} – 1 ) + 2( \sqrt[]{6} + 2 ) – 4( \sqrt[]{6} + 3 ) – \sqrt[]{6}$
    ⇔ $M = 3\sqrt[]{6} – 3 + 2\sqrt[]{6} + 4 – 4\sqrt[]{6} – 12 – \sqrt[]{6}$
    ⇔ $M = – 11$

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222-9+11+12:2*14+14 = ? ( )

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