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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 15/√6 + 1 + 4/ √ 6 -2 + 12/√ 6 -3 – √6

Toán Lớp 9: 15/√6 + 1 + 4/ √ 6 -2 + 12/√ 6 -3 – √6

Comments ( 1 )

  1. Giải đáp:
    $A = – 11$
    Lời giải và giải thích chi tiết:
    Ta có : $A = \frac{15}{\sqrt[]{6}+1} + \frac{4}{\sqrt[]{6}-2} + \frac{12}{\sqrt[]{6}-3} – \sqrt[]{6}$
    ⇔ $A = \frac{15(\sqrt[]{6}-1)}{(\sqrt[]{6}+1)(\sqrt[]{6}-1)} + \frac{4(\sqrt[]{6}+2)}{(\sqrt[]{6}-2)(\sqrt[]{6}+2)} + \frac{12(\sqrt[]{6}+3)}{(\sqrt[]{6}-3)(\sqrt[]{6}+3)} – \sqrt[]{6}$
    ⇔ $A = \frac{15(\sqrt[]{6}-1)}{6-1} + \frac{4(\sqrt[]{6}+2)}{6-4} + \frac{12(\sqrt[]{6}+3)}{6-9} – \sqrt[]{6}$
    ⇔ $A = \frac{15(\sqrt[]{6}-1)}{5} + \frac{4(\sqrt[]{6}+2)}{2} + \frac{12(\sqrt[]{6}+3)}{-3} – \sqrt[]{6}$
    ⇔ $A = 3( \sqrt[]{6} – 1 ) + 2( \sqrt[]{6} + 2 ) – 4( \sqrt[]{6} + 3 ) – \sqrt[]{6}$
    ⇔ $A = 3\sqrt[]{6} – 3 + 2\sqrt[]{6} + 4 – 4\sqrt[]{6} – 12 – \sqrt[]{6}$
    ⇔ $A = – 11$

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222-9+11+12:2*14+14 = ? ( )