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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: (( √15- √5)/(1- √3)+( √14- √7)/(1- √2)):1/ √7- √5

Toán Lớp 9: (( √15- √5)/(1- √3)+( √14- √7)/(1- √2)):1/ √7- √5

Comments ( 2 )

  1. Giải đáp:
    $A = – 2$
    Lời giải và giải thích chi tiết:
    Ta co :
    $A = ( \frac{\sqrt[]{15}-\sqrt[]{5}}{1-\sqrt[]{3}} + \frac{\sqrt[]{14}-\sqrt[]{7}}{1-\sqrt[]{2}} ) : \frac{1}{\sqrt[]{7}-\sqrt[]{5}}$
    ⇔ $A = ( \frac{\sqrt[]{5}(\sqrt[]{3}-1)}{1-\sqrt[]{3}} + \frac{\sqrt[]{7}(\sqrt[]{2}-1)}{1-\sqrt[]{2}} ) . ( \sqrt[]{7} – \sqrt[]{5} )$
    ⇔ $A = ( – \sqrt[]{5} – \sqrt[]{7} ) . ( \sqrt[]{7} – \sqrt[]{5} )$
    ⇔ $A = – ( \sqrt[]{7} + \sqrt[]{5} ) . ( \sqrt[]{7} – \sqrt[]{5} )$
    ⇔ $A = – ( 7 – 5 )$
    ⇔ $A = – 2$

  2. ((\sqrt{15}-\sqrt{5})/(1-\sqrt{3})+(\sqrt{14}-\sqrt{7})/(1-\sqrt{2})):(1)/(\sqrt{7}-\sqrt{5})
    =(-(\sqrt{5}(\sqrt{3}-1))/(\sqrt{3}-1)-(\sqrt{7}(\sqrt{2}-1))/(\sqrt{2}-1)):(1)/(\sqrt{7}-\sqrt{5})
    =(-\sqrt{5}-\sqrt{7}).(\sqrt{7}-\sqrt{5})
    =-\sqrt{35}+5-\sqrt{49}+\sqrt{35}
    =5-7
    =-2
     

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222-9+11+12:2*14+14 = ? ( )

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