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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 1) so sánh 5 ∛6 và 6 ∛5 2) rút gọn ∛135/∛5 – ∛54 ÷ ∛4 3)tìm x a) ∛2x+1=3 b) ∛x-1 + 1 = x

Toán Lớp 9: 1) so sánh
5 ∛6 và 6 ∛5
2) rút gọn

∛135/∛5 – ∛54 ÷ ∛4
3)tìm x
a) ∛2x+1=3
b) ∛x-1 + 1 = x

Comments ( 2 )

  1. Giải đáp+giải thích các bước giải:
    1, so sán:
    Ta có:
    $5\sqrt[3]{6}=\sqrt[3]{125}.\sqrt[3]{6}=\sqrt[3]{125.6}=\sqrt[3]{750}$
    $6\sqrt[3]{5}=\sqrt[3]{216}.\sqrt[3]{5}=\sqrt[3]{216.5}=\sqrt[3]{1080}$
    do $\sqrt[3]{750}<\sqrt[3]{1080}$
    nên ⇒ $5\sqrt[3]{6}<6\sqrt[3]{5}$
    2, rút gọn:
    $\dfrac{\sqrt[3]{135}}{\sqrt[3]{5}}-\sqrt[3]{54}:\sqrt[3]{4}$
    $=\dfrac{\sqrt[3]{135}}{\sqrt[3]{5}}-\dfrac{\sqrt[3]{54}}{\sqrt[3]{4}}$
    $=\sqrt[3]{\dfrac{135}{5}}-\sqrt[3]{\dfrac{54}{4}}$
    $=\sqrt[3]{27}-\sqrt[3]{\dfrac{27}{2}}$
    $=3-\dfrac{\sqrt[3]{27}}{\sqrt[3]{2}}$
    $=3-\dfrac{3}{\sqrt[3]{2}}$
    3, tìm x:
    a)
    $\sqrt[3]{2x+1}=3$
    $\sqrt[3]{2x+1}=\sqrt[3]{27}$
    $2x+1=27$
    $2x=26$
    $x=13$
    $\text{Vậy a=13}$
    b)
    $\sqrt[3]{x-1} +1 =x$
    $\sqrt[3]{x-1}=x-1$
    $\sqrt[3]{x-1}=\sqrt[3]{(x-1)^3}$
    $x-1=(x-1)^3$
    $(x-1)-(x-1)^3=0$
    $(x-1)[1-(x-1)^2)=0$
    $(x-1)(1-x+1)(1+x-1)=0$
    $x(x-1)(2-x)=0$
    ⇒\(\left[ \begin{array}{l}x=0\\x-1=0\\2-x=0\end{array} \right.\) 
    ⇔\(\left[ \begin{array}{l}x=0\\x=1\\x=2\end{array} \right.\) 
    $\text{Vậy…}$

  2. 5/∛6 và 6∛5
    Ta có 6∛5=∛6³.5=∛1080
    Vì 1080>6
    ⇒∛6<6∛5
    2) rút gọn
    $\frac{∛135}{∛5}$- $\frac{∛54}{∛4}$ 
    =$\frac{∛135.∛4}{∛5.∛4}$- $\frac{∛54.∛5}{∛4.∛5}$ 
    =$\frac{∛135.∛4-∛54.∛5}{∛20}$
    =$\frac{∛540-∛270}{∛20}$
    =$\frac{∛20(∛27-∛13.5}{∛20)}$
    =∛27-∛13.5
    3)Tìm x
    a)∛2x +1=3
    ⇔∛2x=2
    ⇔2x=2³
    ⇔x=4
    b)∛x-1+1=x
    ⇔∛x=x
    ⇔x=x³
    ⇔1=x²
    ⇔x=±1
                      
     

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222-9+11+12:2*14+14 = ? ( )

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