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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 1 rút gọn A= $\sqrt{3-2\sqrt{2}}$ – $\sqrt{6-4\sqrt{2}}$

Toán Lớp 9: 1 rút gọn
A= $\sqrt{3-2\sqrt{2}}$ – $\sqrt{6-4\sqrt{2}}$

Comments ( 2 )

  1. A = \sqrt{3-\sqrt{2}} – \sqrt{6-4\sqrt{2}}
    = $\sqrt{(\sqrt{2}-1)^2}$ – \sqrt{(2-\sqrt{2})^2}
    = |\sqrt{2}-1| – |2-\sqrt{2}|
    = \sqrt{2} – 1 – (2-\sqrt{2})
    = \sqrt{2} – 1 – 2 + \sqrt{2}
    = 2\sqrt{2} – 3
     

  2. Giải đáp:
    A=2sqrt{2}-3
    Lời giải và giải thích chi tiết:
    A=sqrt{3-2sqrt{2}}-sqrt{6-4sqrt{2}}
    A=sqrt{(sqrt{2})^2-2.sqrt{2}.1+1^2}-sqrt{6-2.2sqrt{2}}
    A=sqrt{(sqrt{2}-1)^2}-sqrt{2^2-2.2.sqrt{2}+(sqrt{2})^2}
    A=sqrt{(sqrt{2}-1)^2}-sqrt{(2-sqrt{2})^2}
    A=|sqrt{2}-1|-|2-sqrt{2}|
    A=sqrt{2}-1-2+sqrt{2}
    A=2sqrt{2}-3
    Giải thích:
    |sqrt{2}-1|=sqrt{2}-1 vì sqrt{2}>sqrt{1}=1
    |2-sqrt{2}|=2-sqrt{2} vì sqrt{4}(=2)>sqrt{2}

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222-9+11+12:2*14+14 = ? ( )

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