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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: viết biểu thức dưới dạng tổng bình phương(khai triển hằng đẳng thức) a, x^2 + 10x +26 +y^2+2y b, X^2 – 6x +13+ y^2+2y c, 4x^2 – 4x +1 +

Toán Lớp 8: viết biểu thức dưới dạng tổng bình phương(khai triển hằng đẳng thức)
a, x^2 + 10x +26 +y^2+2y
b, X^2 – 6x +13+ y^2+2y
c, 4x^2 – 4x +1 + 2z^2 – 2z

Comments ( 2 )

  1. Giải đáp:
    $\\$
    a,
    x^2 + 10x + 26 + y^2 + 2y
    = x^2 + 10x + 25 + y^2 + 2y + 1
    = [x^2 + 10x + 25] + [y^2 + 2y + 1]
    = [x^2 + 2 . 5x + 5^2] + [y^2 + 2 . 1y + 1^2]
    = (x+5)^2 + (y+1)^2
    $\\$
    b,
    x^2 – 6x + 13 + y^2 + 2y
    = x^2 – 6x +9 + y^2 + 2y + 1 + 3
    = [x^2-6x+9] + [y^2+2y+1] + 3
    = [x^2 – 2 . 3x + 3^2] + [y^2 + 2 . 1y + 1^2] + 3
    = (x-3)^2 + (y + 1)^2 + 3
    $\\$
    c,
    4x^2 – 4x + 1 + 2z^2 – 2z
    = 4x^2 – 4x + 4 + 2z^2 – 2z + 1 – 4
    = [4x^2 – 4x + 4] + [2z^2 – 2z + 1]-4
    = 4 [x^2 -x + 1] + 2 [z^2 – z + 1/2]-4
    = 4 [x^2 – 2 . 1/2x  + 1/4 + 3/4] + 2[ z^2 – 2 . 1/2z + 1/4 + 1/4] – 4
    = 4 [x^2 – 2 . 1/2x + (1/2)^2 + 3/4] + 2 [z^2 – 2 . 1/2z + (1/2)^2 + 1/4] – 4
    = 4 (x-1/2)^2 + 3 + 2 (z-1/2)^2 + 1/2-4
    = 4 (x-1/2)^2 + 2 (z-1/2)^2 + (3 + 1/2-4)
    = 4 (x-1/2)^2 + 2 (z-1/2)^2 -1/2
     

  2. \text{a)}
    x^2 + 10x + 26 +y^2 + 2y
    = (x^2+10x + 25) + (y^2 +2y +1)
    = (x+5)^2 + (y+1)^2
    $\\$
    \text{b)}
    x^2 – 6x +13 + y^2 +2y
    = (x^2 –  6x + 9) + (y^2+2y +1)+3
    = (x -3)^2 + (y+1)^2+3 
    $\\$
    \text{c)}
    4x^2 -4x+1 + 2z^2 -2z
    = (4x^2 – 4x + 4)   + (2z^2 – 2z +1) – 4
    =  4(x^2 – x + 1) + 2(z^2 – z + 1/2) -4
    = 4(x^2 – 2 . x . 1/2 + 1/4 + 3/4) + 2(z^2 – 2 . z . 1/2 + 1/4  +1/4) -4
    = 4(x^2 – 2 . x . 1/2 + 1/4) + 3 + 2(z^2 – 2 . z . 2/2 +1/4) +1/2 -4
    = 4(x-1/2)^2 + 2(z- 1/2)^2  -1/2
     

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222-9+11+12:2*14+14 = ? ( )