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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x $\text{x – 2 = ( 2 – x }$ $)^{2}$

Toán Lớp 8: Tìm x
$\text{x – 2 = ( 2 – x }$ $)^{2}$

Comments ( 2 )

  1. Có:
    (2-x)^2 = 4 – 4x + x^2
    (x-2)^2 = x^2 – 4x + 4
    => (2-x)^2 = (x-2)^2
    => x-2 = (x-2)^2
    => 0 = (x-2)^2 – (x-2)
    => 0 = (x-2-1)(x-2)
    => 0 = (x-2)(x-3)
    \(\left[ \begin{array}{l}x-2=0 => x = 2\\x-3 = 0 => x = 3\end{array} \right.\)
    => x in {2;3}
     

  2. Lời giải:
    (x-2)=(2-x)^2
    ⇔(x-2)=(x-2)^2
    ⇔(x-2)-(x-2)^2=0
    ⇔(x-2)(x-2-1)=0
    ⇔(x-2)(x-3)=0
    $⇔\left[\begin{matrix}x-2=0\\ x-3=0\end{matrix}\right.$
    $⇔\left[\begin{matrix}x=2\\ x=3\end{matrix}\right.$
    Vậy x∈{2;3}

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222-9+11+12:2*14+14 = ? ( )

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