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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x x mũ 3 -10 = 0

Toán Lớp 8: tìm x x mũ 3 -10 = 0

Comments ( 2 )

  1. Giải đáp:
     $S=\{0;-\sqrt{10};\sqrt{10}\}$
    Lời giải và giải thích chi tiết:
    $x^3-10x=0$
    $⇔x(x^2-10)=0$
    $⇔x(x-\sqrt{10})(x+\sqrt{10})=0$
    $⇔\left[ \begin{array}{l}x=0\\x=\sqrt{10}\\x=-\sqrt{10}\end{array} \right.$
    Vậy $S=\{0;-\sqrt{10};\sqrt{10}\}$.

  2. x^3 – 10x = 0
    <=> x(x^2 – 10) = 0
    <=> \(\left[ \begin{array}{l}x=0\\x^2-10 = 0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x^2 = 10\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x= ± (√10)\end{array} \right.\) 
    Vậy x∈{0;√10; -√10}

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222-9+11+12:2*14+14 = ? ( )