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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x l. 4 – 9x^2- 16^x = 0 m. 3 – 2x + 16x^2 = 0

Toán Lớp 8: Tìm x
l. 4 – 9x^2- 16^x = 0
m. 3 – 2x + 16x^2 = 0

Comments ( 2 )

  1. i)
    4-9x^2-16x^2=0
    <=>4-25x^2=0
    <=>(2-5x)(2+5x)=0
    <=>\(\left[ \begin{array}{l}2-5x=0\\2+5x=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=\dfrac{2}{5}\\x=-\dfrac{2}{5}\end{array} \right.\) 
    Vậy S={2/5;-2/5}
    m)
    3-2x+16x^2=0
    <=>16(x^2-1/8x+3/16)=0
    <=>16[(x-1/16)^2+47/256]=0
    <=>16(x-1/16)^2+47/16=0
    <=>16(x-1/16)^2=-47/16
    Vì 16(x-1/16)^2>=0∀x
    Mà 16(x-1/16)^2=-47/16 (vô lí)
    Vậy phương trình đã cho vô nghiệm.

  2. l) 4-9x^2-16x^2=0
    <=> 4-25x^2=0
    <=> 2^2-(5x)^2=0
    <=> (2-5x)(2+5x)=0
    <=> [(2-5x=0),(2+5x=0):}
    <=>\(\left[ \begin{array}{l}x=\dfrac{2}{5}\\x=\dfrac{-2}{5}\end{array} \right.\) 
    Vậy S={2/5;-2/5}
    m) 3-2x+16x^2=0
    <=>(4x)^2-2.4x. 1/4+1/16+47/16=0
    <=> (4x-1/4)^2+47/16=0 (\text{vô lý})
    Vậy S=∅

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222-9+11+12:2*14+14 = ? ( )