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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tim gia tri lon nhat cua cac bieu thuc C=5x-3x^2+2,D=-8x^2+4xy-y^2+3

Toán Lớp 8: tim gia tri lon nhat cua cac bieu thuc C=5x-3x^2+2,D=-8x^2+4xy-y^2+3

Comments ( 1 )

  1. Trả lời:
    Ta có: C=5x-3x^2+2
    =>-C=3x^2-5x-2
    =>-C=3(x^2-5/3x-2/3)
    =>-C=3(x^2-2.x.5/6+25/36-49/36)
    =>-C=3(x-5/6)^2-49/12>=-49/12
    =>C<=-49/12
    =>Max_{C} = -49/12
    Dấu “=” xảy ra:
    <=> x-5/6=0
    =>x=5/6
    Vậy Max_{C} = -49/12<=>x=5/6
    $\\$
    Ta có: D=-8x^2+4xy-y^2+3
    =>-D=8x^2-4xy+y^2-3
    =>-D= (4x^2-4xy+y^2)+4x^2-3
    =>-D=(2x-y)^2 +4x^2-3>=-3
    =>D<=3
    =>Max_{D} = 3
    Dấu “=” xảy ra:
    <=>$\begin{cases} 2x-y=0\\x^2=0 \end{cases}$
    =>$\begin{cases} 2x=y\\x=0 \end{cases}$
    =>x=y=0
    Vậy Max_{D} = 3<=>x=y=0

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222-9+11+12:2*14+14 = ? ( )