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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết: a/ 8×3 – 50x = 0 b/ x3 – x2 – x + 1 = 0 c/ 4×2 – 25 – ( 2x + 5 )( 2x + 7 ) = 0

Toán Lớp 8: Tìm x biết:
a/ 8×3 – 50x = 0
b/ x3 – x2 – x + 1 = 0
c/ 4×2 – 25 – ( 2x + 5 )( 2x + 7 ) = 0

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    a, 8x^3-50x=0
    <=> 2x(4x^2-25) = 0
    <=> 2x(2x+5)(2x-5) = 0
    <=> \(\left[ \begin{array}{l}2x=0\\2x+5=0\\2x-5=0\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=0\\x=-\dfrac52\\x=\dfrac52\end{array} \right.\) 
    Vậy S = {-5/2,5/2,0}
    b, x^3-x^2-x+1=0
    <=> -(x-1)+x^2(x-1) = 0
    <=> (x-1)(x^2-1) = 0
    <=> (x-1)^2(x+1) = 0
    <=>\(\left[ \begin{array}{l}x-1=0\\x+1=0\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=1\\x=-1\end{array} \right.\) 
    Vậy S = {-1,1}
    c, 4x^2-25-(2x+5)(2x+7) = 0
    <=> 4x^2 – (2x+5)(2x+7) = 25
    <=> 4x^2 – 4x^2 – 24x – 35 = 25
    <=> -24x – 35 = 25
    <=> -24x = 60
    <=> x = -5/2
    Vậy S = {-5/2}

  2. Lời giải và giải thích chi tiết:
    a, \ 8x^3-50x=0
    <=> 2x(4x^2-25)=0
    <=> 2x(2x-5)(2x+5)=0
    <=> [(2x=0),(2x-5=0),(2x+5=0):} <=>  \(\left[ \begin{array}{l}x=0\\x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{array} \right.\) 
    Vậy x in {0;5/2;-5/2}
    b, \ x^3-x^2-x+1=0
    <=> x^2(x-1)-(x-1)=0
    <=> (x^2-1)(x-1)=0
    <=> (x-1)(x+1)(x-1)=0
    <=> (x+1)(x-1)^2=0
    <=> [(x+1=0),(x-1=0):} <=> [(x=-1),(x=1):}
    Vậy x in {-1;1}
    c, \ 4x^2-25-(2x+5)(2x+7)=0
    <=> (2x-5)(2x+5)-(2x+5)(2x+7)=0
    <=> (2x+5)(2x-5-2x-7)=0
    <=> (2x+5)(-12)=0
    <=> 2x+5=0
    <=> x=-5/2
    Vậy x=-5/2

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222-9+11+12:2*14+14 = ? ( )

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