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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết a,(2x+5)^2+(4x+10)(3-x)+x^2-6x+9=0 b, (x-2)^2-(x-3)(x+2)=0 c,5x(x-2013)-2x+4026=0

Toán Lớp 8: Tìm x biết
a,(2x+5)^2+(4x+10)(3-x)+x^2-6x+9=0
b, (x-2)^2-(x-3)(x+2)=0
c,5x(x-2013)-2x+4026=0

Comments ( 1 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    ${a) (2x+5)^2+(4x+10)(3-x)+x^2-6x+9=0}$
    ⇔${4x^2+20x+25+12x-4x^2+30-10x+x^2-6x+9=0}$
    ⇔${ x^2 +16x+64=0}$
    ⇔${(x+8)^2=0}$
    ⇔${x+8=0}$
    ⇔${x=-8}$
    ${b) (x-2)^2-(x-3)(x+2)=0}$
    ${b) (x^2-4x+4-(x^2+2x-3x-6)=0}$
    ${b) (x^2-4x+4-x^2-2x+3x+6)=0}$
    ${b) -3x+10=0}$
    ${b) -3x=-10}$
    ${b) x= }$$\frac{-10}{-3}$
    ${b)x= }$$\frac{10}{3}$
    ${c) 5x(x-2013)-2x+4026=0}$
    ${c) 5x(x-2013)-2(x-2013)=0}$
    ${c) (x-2013)(5x-2)=0}$
    \(\left[ \begin{array}{l}x-2013=0\\5x-2=0\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=2013\\5x=2\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=2013\\x=\frac{2}{5} \end{array} \right.\) 

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222-9+11+12:2*14+14 = ? ( )

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