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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x biết a) ($x+2)^{3}$ -(x-3)( $x^{2}$ +3x+9)+6 ($x+1)^{2}$ =15 b) $6x^{2}$ -6x(-2+x)=36

Toán Lớp 8: Tìm x biết
a) ($x+2)^{3}$ -(x-3)( $x^{2}$ +3x+9)+6 ($x+1)^{2}$ =15
b) $6x^{2}$ -6x(-2+x)=36

Comments ( 2 )

  1. Giải đáp:
    Lời giải và giải thích chi tiết:
     

    toan-lop-8-tim-biet-a-2-3-3-2-3-9-6-1-2-15-b-6-2-6-2-36

  2. a)
    (x-2)^3-(x-3)(x^2+3x+9)+6(x+1)^2=15
    \to x^3-6x^2+12x-8-(x^3-27)+6(x^2+2x+1)=15
    \to x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=15
    \to 24x+25=15
    \to 24x=-10
    \to x=-5/12
    Vậy x=-5/12
    b)
    6x^2-6x(-2+x)=36
    \to 6x^2+12x-6x^2=36
    \to 12x=36
    \to x=3
    Vậy x=3
     

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222-9+11+12:2*14+14 = ? ( )

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