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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x, biết x^2 – 4 – (x+2)(3x-1)=0

Toán Lớp 8: Tìm x, biết
x^2 – 4 – (x+2)(3x-1)=0

Comments ( 2 )

  1. x^2 – 4 – (x + 2)(3x – 1) = 0
    <=> (x^2 – 4) – (x + 2)(3x – 1) = 0
    <=> (x + 2)(x – 2) – (x + 2)(3x – 1) = 0
    <=> (x + 2)(x – 2 – 3x + 1) = 0
    <=> (x + 2)(- 2x – 1) = 0
    <=> \(\left[ \begin{array}{l}x + 2 = 0\\- 2x – 1 = 0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=-2\\x=-\dfrac{1}{2}\end{array} \right.\) 
    Vậy x in {- 2; – 1/2}

  2. $\textit{Giải đáp + Lời giải và giải thích chi tiết:}$
    $\text{Áp dụng hằng đẳng thức $a^2-b^2=(a-b)(a+b)$}$
    x^2-4-(x+2)(3x-1)=0
    ⇔(x-2)(x+2)-(x+2)(3x-1)=0
    ⇔(x+2)(x-2-3x+1)=0
    ⇔(x+2)(-2x-1)=0
    \(\left[ \begin{array}{l}x+2=0\\-2x-1=0\end{array} \right.\)
    \(\left[ \begin{array}{l}x=-2\\-2x=1\end{array} \right.\)
    \(\left[ \begin{array}{l}x=-2\\x=-\dfrac{1}{2}\end{array} \right.\)
    $Vậy$ x∈{-2;-1/2}
     

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222-9+11+12:2*14+14 = ? ( )