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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x a)x mũ 2 -4=0 b)16x mũ 2 -1 =0 c)x mũ 3 -x=0 d) 4x mũ 2 ( x-2) tất cả mũ 2 =0

Toán Lớp 8: Tìm x
a)x mũ 2 -4=0
b)16x mũ 2 -1 =0
c)x mũ 3 -x=0
d) 4x mũ 2 ( x-2) tất cả mũ 2 =0

Comments ( 2 )

  1. $@Shun$~
    Tìm x:
    a) x^2 – 4 = 0
    ⇔ x^2 – 2^2 = 0
    ⇔ (x-2)(x+2) = 0
    ⇔ $\left[\begin{matrix} x-2=0\\ x+2=0\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x=2\\ x=-2\end{matrix}\right.$
    Vậy x∈{2; -2}
    b) 16x^2 – 1 = 0
    ⇔ 16x^2 -1^2 = 0
    ⇔ (16x – 1)(16x+1) = 0
    ⇔ $\left[\begin{matrix} 16x-1=0\\ 16x+1=0\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} 16x=1\\ 16x=-1\end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x= \dfrac{1}{16} \\ x=\dfrac{-1}{16} \end{matrix}\right.$
    Vậy x∈{ 1/16 ; – 1/16}
    c) x^3 – x = 0
    ⇔ x(x^2 – 1) = 0
    ⇔ x(x -1)(x+1) = 0
    ⇔ $\left[\begin{matrix} x=0 \\ x-1= 0 \\ x+1 = 0 \end{matrix}\right.$
    ⇔$\left[\begin{matrix} x=0 \\ x=1 \\ x= -1 \end{matrix}\right.$
    Vậy x∈{0; 1; -1}
    d) 4x^2 . (x-2)^2 = 0
    ⇔ $\left[\begin{matrix} 4x^2 = 0 \\ (x-2)^2= 0 \end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x^2=0 \\ x-2=0 \end{matrix}\right.$
    ⇔ $\left[\begin{matrix} x=0 \\ x=2 \end{matrix}\right.$
    Vậy x∈{0 ; 2}

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222-9+11+12:2*14+14 = ? ( )