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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tim x X+5×2=0 B 2(x+5)-x2-5x=0

Home/ Toán Lớp 8: Tim x X+5×2=0 B 2(x+5)-x2-5x=0

Toán Lớp 8: Tim x X+5×2=0 B 2(x+5)-x2-5x=0

Tháng Tám 7, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Tim x
X+5×2=0
B
2(x+5)-x2-5x=0

Comments ( 2 )

  1. mocmien87
    mocmien87
    7 Tháng Tám, 2022 at 10:57 sáng
    Reply
    x + 5x^{2} = 0
    => x(1 +5x) = 0
    => \(\left[ \begin{array}{l}x=0\\1 + 5x=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=0\\5x=-1\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=0\\x=-1/5\end{array} \right.\) 
    Vậy x ∈ { 0 ; -1/5 }
    B = 2(x + 5) – x^{2} – 5x = 0
    B = 2(x + 5) – x(x + 5) = 0
    B = (2 – x)(x + 5) = 0
    B =\(\left[ \begin{array}{l}2 – x = 0\\x + 5 = 0\end{array} \right.\) 
    B = \(\left[ \begin{array}{l}x=2\\x=-5\end{array} \right.\) 
    Vậy x ∈ { 2 ; -5 }
     

  2. cobebongdem
    cobebongdem
    7 Tháng Tám, 2022 at 10:57 sáng
    Reply
    a, x + 5x^2 = 0
    <=> x (1 + 5x) = 0
    <=>  \(\left[ \begin{array}{l}x=0\\x=1 + 5x\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=0\\x=- \dfrac{1}{5}\end{array} \right.\) 
    Vậy x in {0; – 1/5}
    b, 2 (x + 5) – x^2 – 5x = 0
    <=> 2 (x + 5) – x (x + 5) = 0
    <=> (x + 5)(2 – x) = 0
    <=> \(\left[ \begin{array}{l}x + 5 = 0\\2 – x = 0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=-5\\x=2\end{array} \right.\) 
    Vậy x in {-5; 2}

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222-9+11+12:2*14+14 = ? ( )

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