Toán Lớp 8: tìm x
$(x-2)(2x+1)-(x-2)^2=0$
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Toán Lớp 8: tìm x
$(x-2)(2x+1)-(x-2)^2=0$
Comments ( 2 )
(x-2)(2x+1)-(x-2)² =0
=>(x-2)( 2x+1-x+2)=0
=>(x-2) (x+3) =0
=>x-2=0=>x=2
=>x+3=0=>x=-3
Vậy x=2 hoặc x=-3
$\text{ ( x – 2 )(2x + 1) – $( x – 2 )^{2}$ = 0 }$
$\text{ ( x – 2 )( 2x + 1 – x + 2 ) = 0 }$
$\left[\begin{matrix} x – 2 = 0\\ 2x + 1 – x + 2 = 0\end{matrix}\right.$
$\left[\begin{matrix} x=2\\ x = -3\end{matrix}\right.$