Toán Lớp 8: Thực hiện phép chia: (x³+2x²-2x+1):(x²+3x+1)
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Toán Lớp 8: Thực hiện phép chia: (x³+2x²-2x+1):(x²+3x+1)
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\left( {{x^3} + 2x – 2x – 1} \right):\left( {x + 3x – 1} \right)\\
= \left[ {\left( {{x^3} – 1} \right) + \left( {2{x^2} – 2x} \right)} \right]:\left( {x + 3x – 1} \right)\\
= \left[ {\left( {x – 1} \right)\left( {{x^2} + x + 1} \right) + 2x\left( {x – 1} \right)} \right]:\left( {x + 3x – 1} \right)\\
= \left[ {\left( {x – 1} \right)\left( {{x^2} + x + 1 + 2x} \right)} \right]:\left( {x + 3x – 1} \right)\\
= \left[ {\left( {x – 1} \right)\left( {x + 3x – 1} \right)} \right]:\left( {x + 3x – 1} \right)\\
= x – 1
\end{array}\]