Toán Lớp 8: thành nhân tử
x^3+3x^2-3x-1
x^4-5x^2+4
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Toán Lớp 8: thành nhân tử
x^3+3x^2-3x-1
x^4-5x^2+4
Comments ( 2 )
= (x^3-1)+(3x^2-3x)
= (x-1)(x^2+x+1)+3x(x-1)
= (x-1)(x^2+x+1+3x)
= (x-1)(x^2+4x+1)
$\\$
x^4-5x^2+4
= x^4-4x^2-x^2+4
= x^2(x^2-4)-(x^2-4)
= (x^2-4)(x^2-1)
= (x-2)(x+2)(x-1)(x+1)