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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: so sánh 6(7^2+1)(7^4+1)(7^8+1)(7^16+1) và 7^32/8 giúp mình với ;-;

Toán Lớp 8: so sánh 6(7^2+1)(7^4+1)(7^8+1)(7^16+1) và 7^32/8 giúp mình với ;-;

Comments ( 2 )

  1. Đặt:
    A=6(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    B=7^32/8
    Ta có:
    +)A=6(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    →8A=8.6(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    8A=48(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    8A=(7^2-1)(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    8A=(7^4-1)(7^4+1)(7^8+1)(7^16+1)
    8A=(7^8-1)(7^8+1)(7^16+1)
    8A=(7^16-1)(7^16+1)
    8A=7^32-1
    +)B=7^32/8
    →8B=8. 7^32/8
    8B=7^32
    Do 8A=7^32-1<8B=7^32 nên A<B
    hay 6(7^2+1)(7^4+1)(7^8+1)(7^16+1)<7^32/8
    Vậy 6(7^2+1)(7^4+1)(7^8+1)(7^16+1)<7^32/8

  2. Giải đáp + Lời giải và giải thích chi tiết:
    6(7^2+1)(7^4+1)(7^8+1)(7^16+1)
    =(8.6(7^2+1)(7^4+1)(7^8+1)(7^16+1))/8
    =(48(7^2+1)(7^4+1)(7^8+1)(7^16+1))/8
    =((7^2-1)(7^2+1)(7^4+1)(7^8+1)(7^16+1))/8
    =((7^4-1)(7^4+1)(7^8+1)(7^16+1))/8
    =((7^8-1)(7^8+1)(7^16+1))/8
    =((7^16-1)(7^16+1))/8
    =(7^32-1)/8
    Vì 7^32>7^32-1
    =>(7^32)/8>(7^32-1)/8
    Vậy (7^32)/8>6(7^2+1)(7^4+1)(7^8+1)(7^16+1)
     

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222-9+11+12:2*14+14 = ? ( )