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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn biểu thức : P = x( x + 2) +2(x – 3)^2-3(x + 1)( x – 1) A =2x( x – 1) – ( x -2)(x +2) – ( x – 3)^2 Tìm a để đa thức f(x)=2x^3 –

Toán Lớp 8: Rút gọn biểu thức :
P = x( x + 2) +2(x – 3)^2-3(x + 1)( x – 1)
A =2x( x – 1) – ( x -2)(x +2) – ( x – 3)^2
Tìm a để đa thức f(x)=2x^3 – 3x^2 + x + a chia hết cho đa thức x + 2
Giúp mik v ạ, mik sắp thi r
Tìm x biết 3x ( x + 3) – x = 3
Tìm x biết: 2x( x – 1) – x + 1=0

Comments ( 1 )

  1. Giải đáp:
    P = x.( x + 2) +2.(x – 3)^2-3.(x + 1).( x – 1)
    -> P = x^2 + 2x + 2.(x^2 – 6x + 9) – 3.(x^2 – 1)
    -> P = x^2 + 2x + 2x^2 – 12x + 18 – 3x^2 + 3
    -> P = (x^2 + 2x^2 – 3x^2) + (2x – 12x) + (18 + 3)
    -> P = -10x + 21
    A = 2x.( x – 1) – ( x -2).(x +2) – ( x – 3)^2
    -> A = 2x^2 – 2x – (x^2 – 4) – (x^2 – 6x + 9)
    -> A = 2x^2 – 2x – x^2 + 4 – x^2 + 6x – 9
    -> A = (2x^2 – x^2 – x^2) + [(-2x) + 6x] + (4 – 9)
    -> A = 4x – 5
    ———————-
    f(x) = 2x^3 – 3x^2 + x + a
    f(x) = 2x^3 + 4x^2 – 7x^2 – 14x + 15x + 30 – 30 + a
    f(x) = 2x^2.(x + 2) – 7x.(x + 2) + 15.(x + 2) – 30 + a
    f(x) = (x + 2).(2x^2 – 7x + 15) – 30 + a
    -> f(x) : (x + 2) = 2x^2 – 7x + 15 dư -30 + a
    -> Đa thức f(x) chia hết cho đa thức x + 2
    ↔ -30 + a = 0
    ↔ a = 30
    Vậy a = 30
    ———————-
    3x.(x + 3) – x = 3
    ↔ 3x.(x + 3) – x – 3 = 0
    ↔ 3x.(x + 3) – (x + 3) = 0
    ↔ (x + 3).(3x – 1) = 0
    ↔ $\left[\begin{matrix} x = 3\\ x = \dfrac{1}{3}\end{matrix}\right.$
    Vậy x ∈ {3; 1/3}
    2x.(x – 1) – x + 1 = 0
    ↔ 2x.(x – 1) – (x – 1) = 0
    ↔ (x – 1).(2x – 1) = 0
    ↔ $\left[\begin{matrix} x = 1\\ x = \dfrac{1}{2}\end{matrix}\right.$
    Vậy x ∈ {3; 1/2}
    #dariana

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222-9+11+12:2*14+14 = ? ( )