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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn: b/ ( 2x – 3 )^2 – ( x – 3 ) ( x^2 – 5x + 4 ) c/ ( x + 8 ) ( 2x – 4 ) – ( x – 5 )^2 e/ ( 3x +

Toán Lớp 8: Rút gọn: b/ ( 2x – 3 )^2 – ( x – 3 ) ( x^2 – 5x + 4 )
c/ ( x + 8 ) ( 2x – 4 ) – ( x – 5 )^2
e/ ( 3x + 1 )^2 – 3x ( x + 1 ) ( x – 2 )
f/ ( 3x – 4 ) ( 2 + 3x ) – ( 3x + 5 )^2
i/ ( 2 – 9x ) ( 2 – x ) – ( 3x + 2 )^2
KHÔNG BỎ BƯỚC NHA MN!

Comments ( 2 )

  1. b)( 2x – 3 )^2 – ( x – 3 ) ( x^2 – 5x + 4 )

    = 4x^2−12x+9+(−x+3)(x^2−5x+4)

    = 4x^2−12x+9−x^3+8x^2−19x+12

    = 12x^2−31x+21−x^3

    = −x^3+12x^2−31x+21

    c)( x + 8 ) ( 2x – 4 ) – ( x – 5 )^2

    = 2x^2+12x−32−x^2+10x−25

    = (2−1)x^2+(12+10)x+(−32−25)

    = x^2+22x−57

    e)( 3x + 1 )^2 – 3x ( x + 1 ) ( x – 2 )

    = 9x^2+6x+1−3x^3+3x^2+6x

    = 12x^2+12x+1−3x^3
    = −3x^3+12x^2+12x+1

    f)( 3x – 4 ) ( 2 + 3x ) – ( 3x + 5 )^2

    = 9x^2+18x+8−9x^2−30x−25

    = −12x−17

    i)( 2 – 9x ) ( 2 – x ) – ( 3x + 2 )^2

    = 9x^2−20x+4−9x^2−12x−4

    = −32x+(4−4)

    = −32x

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    b/ ( 2x – 3 )^2 – ( x – 3 ) ( x^2 – 5x + 4 )
    = 4x^2−12x+9+(−x+3)(x^2−5x+4)
    = 4x^2−12x+9−x^3+8x^2−19x+12
    = 12x^2−31x+21−x^3
    = −x^3+12x^2−31x+21
    c/ ( x + 8 ) ( 2x – 4 ) – ( x – 5 )^2
    = 2x^2+12x−32−x^2+10x−25
    = (2−1)x^2+(12+10)x+(−32−25)
    = x^2+22x−57
    e/ ( 3x + 1 )^2 – 3x ( x + 1 ) ( x – 2 )
    = 9x^2+6x+1−3x^3+3x^2+6x
    = 12x^2+12x+1−3x^3
    = −3x^3+12x^2+12x+1
    f/ ( 3x – 4 ) ( 2 + 3x ) – ( 3x + 5 )^2
    = 9x^2+18x+8−9x^2−30x−25
    = −12x−17
    i/ ( 2 – 9x ) ( 2 – x ) – ( 3x + 2 )^2
    = 9x^2−20x+4−9x^2−12x−4
    = −32x+(4−4)
    = −32x

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222-9+11+12:2*14+14 = ? ( )

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