Toán Lớp 8: phân tích thành nhân tử 4????²????²( 2???? + ???? ) + ????²????²( ???? − ???? ) − 4????²????²( 2???? + ???? )

Question

Toán Lớp 8:  phân tích thành nhân tử  4????²????²( 2???? + ???? ) + ????²????²( ???? − ???? ) − 4????²????²( 2???? + ???? )

ngocle44 · Answer

4a^2b^2(2a + b) + b^2c^2(c - b) - 4a^2c^2(2a + c)   = 8a^3b^2 + 4a^2b^3 + b^2c^3 - b^3c^2 - 8a^3c^2 - 4a^2c^3   = 8a^3b^2 - 8a^3c^2 + 4a^2b^3 - 4a^2c^3 + b^2c^3 - b^3c^2   = 8a^3(b^2 - c^2) + 4a^2(b^3 - c^3) - b^2c^2(b - c)   = 8a^3(b - c)(b + c) + 4a^2(b - c)(b^2 + bc + c^2) - b^2c^2(b - c)   = (b - c)[8a^3(b + c) + 4a^2(b^2 + bc + c^2) - b^2c^2]

kimoanh34 · Answer

4a^2b^2(2a + b) + b^2c^2 (c-b) - 4a^2c^2(2a + c)   = 8a^3b^2 + 4a^2b^3 + b^2c^3 - b^3c^2 - 8a^3c^2 + 4a^2c^3   = 8a^3b^2 - 8a^3c^2c+ 4a^2b^3 + 4a^2c^3 + b^2c^3 - b^3c^2   = 8a^3 ( b^2 - c^2) + 4a(b^3-c^3) + b^2c^2( b-c)   = 8a^3 (b+c)(b-c) + 4a(b - c)(b^2 + bc + c^2) + b^2c^2( b-c)   = (b-c)[8a^3 (b+c)+4a(b^2 +bc+c^2) + b^2c^2]     $#Dyn.Shun$       $@Shun - Aqua$