Toán Lớp 8: Phân tích thành nhân tử $x^2 - 4 + 3(x - 2)^2$

$x^{2}$-4+3( $x-2)^{2}$ =($x^{2}$ -4)+3$(x-2)^{2}$ =(x-2)(x+2)+3$(x-2)^{2}$ =(x-2)[(x+2)+3(x-2)] =(x-2)(x+2+3x-6) =(x-2)(4x-4) =(x-2)4(x-1)

#tnvt x^2-4+3(x-2)^2 =(x-2)(x+2)+3(x-2)^2 =(x-2)[x+2+3(x-2)] =(x-2)(x+2+3x-6) =(x-2)(4x-4) =4(x-2)(x-1)

Toán Lớp 8: Phân tích thành nhân tử $x^2 - 4 + 3(x

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