Toán Lớp 8: Phân tích dt thành nhân tử
$x^4+2x^3+x^2-y^2$
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Toán Lớp 8: Phân tích dt thành nhân tử
$x^4+2x^3+x^2-y^2$
Comments ( 2 )
$=x^2(x^2+2x+1)-y^{2}$
$=x^2.(x+1)^2-y^2$
$=(x^2+x)^2-y^2$
$=(x^2+x-y)(x^2+x+y)$