Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích đa thức thành nhân tử a)(x+y+z)^3 b)(x+y+z)^3-x^3-y^3-z^3 đề ko có bị sai nha mn

Toán Lớp 8: Phân tích đa thức thành nhân tử
a)(x+y+z)^3
b)(x+y+z)^3-x^3-y^3-z^3
đề ko có bị sai nha mn

Comments ( 2 )

  1. a)
    (x + y + z)^3
    = [(x + y)+ z]^3
    = (x + y)^3 + 3(x + y)^2z + 3(x + y)z^2 + z^3
    = x^3 + 3x^2y + 3xy^2 + y^3 + 3(x + y)^2z + 3(x + y)z^2 + z^3
    = x^3 + y^3 + z^3 + 3xy(x + y) + 3(x + y)^2z + 3(x + y)z^2
    = x^3 + y^3 + z^3 + 3(x + y)[xy + z(x + y + z)]
    = x^3 + y^3 + z^3 + 3(x + y)(y + z)(z + x)
    b)
    (x + y + z)^3 – x^3 – y^3 – z^3
    = [(x + y)+ z]^3 – x^3 – y^3 – z^3
    = (x + y)^3 + 3(x + y)^2z + 3(x + y)z^2 + z^3 – x^3 – y^3 – z^3
    = x^3 + 3x^2y + 3xy^2 + y^3 + 3(x + y)^2z + 3(x + y)z^2 + z^3 – x^3 – y^3 – z^3
    = x^3 + y^3 + z^3 + 3xy(x + y) + 3(x + y)^2z + 3(x + y)z^2 – x^3 – y^3 – z^3
    = x^3 + y^3 + z^3 + 3(x + y)[xy + z(x + y + z)] – x^3 – y^3 – z^3
    = x^3 + y^3 + z^3 + 3(x + y)(y + z)(z + x) – x^3 – y^3 – z^3
    = 3(x + y)(y + z)(z + x)

  2. Giải đáp+Lời giải và giải thích chi tiết:
     a)(x+y+z)^3
    =[(x+y)+z]^3
    =(x+y)^3+z^3+3(x+y).z.(x+y+z)
    =x^3+y^3+3xy(x+y)+z^3+3(x+y).z.(x+y+z)
    =x^3+y^3+z^3+[3xy(x+y)+3(x+y).z.(x+y+z)]
    =x^3+y^3+z^3+3(x+y)(xy+zx+zy+z^2)
    =x^3+y^3+z^3+3(x+y)[x(y+z)+z(y+z)]
    =x^3+y^3+z^3+3(x+y)(y+z)(x+z)
    b)(x+y+z)^3-x^3-y^3-z^3
    =[(x+y)+z]^3-x^3-y^3-z^3
    =(x+y)^3+z^3+3(x+y).z.(x+y+z)-x^3-y^3-z^3
    =x^3+y^3+3xy(x+y)+z^3+3(x+y).z.(x+y+z)-x^3-y^3-z^3
    =3xy(x+y)+z^3+3(x+y).z.(x+y+z)
    =3(x+y)(xy+zx+zy+z^2)
    =3(x+y)[x(y+z)+z(y+z)]
    =3(x+y)(y+z)(x+z)
                                     
    Áp dụng : (a+b)^3=a^3+3a^2 b+3ab^2+b^3
                                 =a^3+b^3+3ab(a+b)

Leave a reply

222-9+11+12:2*14+14 = ? ( )