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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích đa thức thành nhân tử: $a^{4}$$(^{}$ $b^{}$ $-^{}$ $c^{}$ $)^{}$ $+^{}$ $b^{4}$ $(^{}$ $c^{}$ $-^{}$ $a^{}$ $)^{}$ $+^{}$ $c

Toán Lớp 8: Phân tích đa thức thành nhân tử:
$a^{4}$$(^{}$ $b^{}$ $-^{}$ $c^{}$ $)^{}$ $+^{}$ $b^{4}$ $(^{}$ $c^{}$ $-^{}$ $a^{}$ $)^{}$ $+^{}$ $c^{4}$ $(^{}$ $a^{}$ $-^{}$ $b^{}$ $)^{}$

Comments ( 1 )

  1. a^4(b-c) + b^4(c-a) + c^4(a-b)
    <=> a^4(b-a + a-c) + b^4(c-a) + c^4(a-b)
    <=> a^4(b-a) + a^4(a-c) – b^4(a-c) – c^4(b-a)
    <=> (b-a)(a^4 – c^4) + (a-c)(a^4-b^4)
    <=> (b-a)(a^2 – c^2)(a^2 + c^2) + (a-c)(a^2+b^2)(a^2-b^2)
    <=> (b-a)(a-c)(a+c)(a^2+c^2) + (a-c)(a^2+b^2)(a-b)(a+b)
    <=> (b-a)(a-c)[(a+c)(a^2+c^2) – (a+b)(a^2+b^2)]
    <=> (b-a)(a-c)[a^3 + ac^2 + a^2c + c^3 – a^3 – ab^2 – a^2b – b^3]
    <=> (b-a)(a-c)[c^3 – b^3 + (ac^2-ab^2) + (a^2c – a^2b)]
    <=> (b-a)(a-c)[(c-b)(c^2+bc+b^2) + a(c^2 – b^2) + a^2(c-b)]
    <=> (b-a)(a-c)[(c-b)(c^2 + bc + b^2) + a(c-b)(c+b) + a^2(c-b)]
    <=> (b-a)(a-c)(c-b)(c^2 + bc + b^2 + a(c+b) + a^2)
    <=> (b-a)(a-c)(c-b)(a^2 + b^2 + c^2 + bc + ac + ab)
     

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222-9+11+12:2*14+14 = ? ( )