Toán Lớp 8: Giair pt
x^4 + 6x^3 – 48x^2 + 46x – 9 = 0
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Toán Lớp 8: Giair pt
x^4 + 6x^3 – 48x^2 + 46x – 9 = 0
Comments ( 1 )
⇔(x+5+$\sqrt[]{34}$ )(x+5-$\sqrt[]{34}$ )(x-2+$\sqrt[]{3}$ )(x-2-$\sqrt[]{3}$ )=0
⇔\(\left[ \begin{array}{l}x+5+\sqrt[]{34}=0\\x+5-\sqrt[]{34}=0\\x-2+\sqrt[]{3}=0\\x-2-\sqrt[]{3}=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x+5=-\sqrt[]{34}\\x+5=\sqrt[]{34}\\x-2=-\sqrt[]{3}\\x-2=\sqrt[]{3}\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-\sqrt[]{34}-5\\x=\sqrt[]{34}-5\\x=-\sqrt[]{3}+2\\x=\sqrt[]{3}+2\end{array} \right.\)
Vậy S={$-\sqrt[]{34}-5$;$\sqrt[]{34}-5$;$-\sqrt[]{3}+2$;$\sqrt[]{3}+2$}