Toán Lớp 8: Giải phương trình:
$\frac{2 – x}{2021}$ – 1 = $\frac{1 – x}{2022}$ – $\frac{x}{2023}$
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Toán Lớp 8: Giải phương trình:
$\frac{2 – x}{2021}$ – 1 = $\frac{1 – x}{2022}$ – $\frac{x}{2023}$
Comments ( 1 )
Giải đáp:
$\frac{2−x}{2021}$-1= $\frac{1-x}{2021}$ -$\frac{x}{2023}$
⇔$\frac{x-2}{2021}$+1= $\frac{x-1}{2021}$ +$\frac{x}{2023}$
⇔$\frac{x-2}{2021}$-1= $\frac{x-1}{2021}$ -1 +$\frac{x}{2023}$ -1
⇔$\frac{x-2023}{2021}$-1= $\frac{x-2023}{2022}$ -1 +$\frac{x-2023}{2023}$ -1
⇔(x-2023)($\frac{x-1}{2021}$-$\frac{x-1}{2022}$-$\frac{x-1}{2023}$)=0
Vì:
$\frac{1}{4042}$ < $\frac{1}{2022}$
$\frac{1}{4042}$ < $\frac{1}{2023}$
⇒$\frac{x-1}{2021}$-$\frac{x-1}{2022}$-$\frac{x-1}{2023}$<0
⇔x-2023=0
x=0+2023
x=2023