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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải bài toán bằng cách lập phương trình . (42/x+2)+(20/x-2)=5

Toán Lớp 8: Giải bài toán bằng cách lập phương trình .
(42/x+2)+(20/x-2)=5

Comments ( 2 )

  1. $\dfrac{42}{x+2}+\dfrac{20}{x-2}=5$
    $\leftrightarrow 42(x-2)+20(x+2)=5(x+2)(x-2)$
    $\leftrightarrow 42x-84+20x+40=5(x^2-4)$
    $\leftrightarrow 42x-84+20x+40=5x^2-20$
    $\leftrightarrow 62x-44=5x^2-20$
    $\leftrightarrow 62x-44-5x^2+20=0$
    $\leftrightarrow -5x^2+62x-24=0$
    $\leftrightarrow 5x^2-62x+24=0$
    $\leftrightarrow 5x^2-60x-2x+24=0$
    $\leftrightarrow 5x(x-12)-2(x-12)=0$
    $\leftrightarrow (x-12)(5x-2)=0$
    $\leftrightarrow \left[ \begin{array}{l}x-12=0\\5x-2=0\end{array} \right.$
    $\leftrightarrow \left[ \begin{array}{l}x=12\\x=\dfrac{2}{5}\end{array} \right.$
    Vậy S={12;2/5}

  2. $(\dfrac{42}{x+2})+$$(\dfrac{20}{x-2})=5$
    $MTC=(x+2)(x-2)$
    $⇒\dfrac{42(x-2)}{(x+2)(x-2)}+$$\dfrac{20(x+2)}{(x+2)(x-2)}=\dfrac{5(x+2)(x-2)}{(x+2)(x-2)}$
    $⇔42(x-2)+20(x+2)=5(x+2)(x-2)$
    $⇔42x-84+20x+40=5(x^2-4)$
    $⇔62x-44=5x^2-20$
    $⇔62x-44-5x^2+20=0$
    $⇔5x^2-62x+24=0$
    $⇔5x^2-60x-2x+24=0$
    $⇔5x(x-12)-2(x-12)=0$
    $⇔(x-12)(5x-2)=0$
    $⇔x-12=0; 5x-2=0$
    $⇔x=12; 5x=2$
    ⇔x=12; x=2/5
    Vậy S={12; 2/5}

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222-9+11+12:2*14+14 = ? ( )

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