Toán Lớp 8: ($frac{x+y}{x^2-y^2}$).$frac{x^3+y^3-xy(x+y)}{x+y}$:$frac{1}{x^2-y^2}$=$x^{2}$-$y^{2}$ -

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Toán Lớp 8: ($\frac{x+y}{x^2-y^2}$).$\frac{x^3+y^3-xy(x+y)}{x+y}$:$\frac{1}{x^2-y^2}$=$x^{2}$-$y^{2}$