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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: $\frac{3x-1}{6x+2}$ -$\frac{3x+1}{2-6x}$ -$\frac{6x}{9x^2-1}$

Tháng Tư 19, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: $\frac{3x-1}{6x+2}$ -$\frac{3x+1}{2-6x}$ -$\frac{6x}{9x^2-1}$

Comments ( 2 )

  1. minhtuquynh
    minhtuquynh
    19 Tháng Tư, 2022 at 7:04 chiều
    Reply
    (3x-1)/(6x+2) – (3x+1)/(2-6x) – (6x)/(9x^2 – 1)
    = (3x-1)/(2(3x+1)) – (3x+1)/(2(1-3x)) – (6x)/((3x-1)(3x+1))
    = ((3x-1)(3x-1))/(2(3x+1)(3x-1)) + ((3x+1)(3x+1))/(2(3x-1)(3x+1)) – (6x)/((3x-1)(3x+1))
    = ( 9x^2 – 6x + 1 + 9x^2 + 6x + 1 – 6x )/((3x+1)(3x-1))
    = (18x^2 – 6x)/((3x+1)(3x-1))
    = (6x(3x-1))/((3x+1)(3x-1))
    = (6x)/(3x+1)
     

  2. lanminhngoc
    lanminhngoc
    19 Tháng Tư, 2022 at 7:04 chiều
    Reply
    Giải đáp:
     
    Lời giải và giải thích chi tiết:
     [3x-1]/[6x+2] -[3x+1]/[2-6x] -[6x]/[9x^2-1]
    =[3x-1]/[2(3x+1)]+[3x+1]/[2(3x-1)] -[6x]/[(3x-1)(3x+1)]
    =[(3x-1)(3x-1)]/[2(3x+1)(3x-1)]+[(3x+1)(3x+1)]/[2(3x-1)(3x+1)]-[6x.2]/[2(3x-1)(3x+1)]
    =[9x^2 -6x+1+9x^2 +6x+1-12x]/[2(3x-1)(3x+1)]
    =[(9x^2 +9x^2 )+(-6x+6x-12x)+(1+1)]/[2(3x-1)(3x+1)]
    =[18x^2 -12x+2]/[2(3x-1)(3x+1)]
    =[2(9x^2 -6x+1)]/[2(3x-1)(3x+1)]
    =[2(3x-1)^2]/[2(3x-1)(3x+1)]
    =[3x-1]/[3x+1]
    (Bài tham khảo)

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222-9+11+12:2*14+14 = ? ( )

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