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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Chứng minh rằng: (a+b+c)^3=a^3+b^3+c^3+3(a+b)(b+c)(c+a)

Toán Lớp 8: Chứng minh rằng:
(a+b+c)^3=a^3+b^3+c^3+3(a+b)(b+c)(c+a)

Comments ( 2 )

  1. $\\$
    $\\$
    Xét VT :
    (a+b+c)^3
    = [(a+b)+c]^3
    = (a+b)^3 + c^3 + 3 (a+b) c (a+b+c)
    = a^3 + b^3 +c^3 + 3ab (a+b) + 3 (a+b)c (a+b+c)
    =a^3 + b^3 +c^3 + 3 (a+b) (ab + ac + bc +c^2)
    = a^3 + b^3 +c^3 + 3 (a+b) [(ab+ac)+(bc+c^2)]
    = a^3 + b^3 +c^3 + 3 (a+b)  [a (b+c)+c(b+c)]
    = a^3 + b^3 +c^3 + 3 (a+b)  (a+c)(b+c) (Bằng VP)
    -> Đpcm
     

  2. Giải đáp:
    Ta có : (a+b+c)^3
               = ((a+b)+c)^3 
               = (a+b)^3 +c^3 +3(a+b)c(a+b+c)
               = a^3 + b^3 +3ab(a+b) + c^3 +3(a+b)c(a+b+c)
               = a^3 + b^3 + c^3 + 3(a+b)(ab+c(a+b+c))
               = a^3 + b^3 + c^3 + 3(a+b)(ab+ac+bc+c^2 )
               = a^3+b^3+c^3+3(a+b)(b+c)(c+a) (đpcm)

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222-9+11+12:2*14+14 = ? ( )