Toán Lớp 8: Bài 2 Phân tích thần nhân tử
a)(2x+3)^2 – (x^2 – 6x +9 )
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Toán Lớp 8: Bài 2 Phân tích thần nhân tử
a)(2x+3)^2 – (x^2 – 6x +9 )
Comments ( 2 )
\[\begin{array}{l}
{(2x + 3)^2} – ({x^2} – 6x + 9)\\
\Leftrightarrow {(2x + 3)^2} – {\left( {x – 3} \right)^2}\\
\Leftrightarrow \left( {2x + 3 – x + 3} \right)\left( {2x + 3 + x – 3} \right)\\
\Leftrightarrow \left( {x + 6} \right)\left( {3x} \right)
\end{array}\]