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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: b1:phân tích đa thức thành nhân tử a)4x^2-12x+9 b)4x^2+4x+1 c)1+12x+36x^2 d)(3x+1)^2-4(x-2)^2 e)9(2x+3)^2-4(x+1)^2 f)4b^2c-(b^2+c^2-a^2

Tháng Mười Hai 7, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: b1:phân tích đa thức thành nhân tử
a)4x^2-12x+9
b)4x^2+4x+1
c)1+12x+36x^2
d)(3x+1)^2-4(x-2)^2
e)9(2x+3)^2-4(x+1)^2
f)4b^2c-(b^2+c^2-a^2)^2
GIÚP VỚI Ạ

Comments ( 2 )

  1. aivilanlan
    aivilanlan
    7 Tháng Mười Hai, 2022 at 2:01 sáng
    Reply
    Giải đáp+Lời giải và giải thích chi tiết:
    a)4????²−12????+9
    =4????²−6????−6????+9
    =2????(2????−3)−3(2????−3)
    =(2????−3)(2????−3)
    =(2????−3)²
    b)4x²+4x+1
    =4????²+2????+2????+1
     =2????(2????+1)+2????+1
    =(2????+1)(2????+1)
    =(2????+1)²
    c)1+12x+36x²
    = 36x² + 12x + 1
    =36????²+6????+6????+1
    =6????(6????+1)+6????+1
    =(6????+1)(6????+1)
    =(6????+1)²
    d)(3x+1)²-4(x-2)²
    =(3????+1)(3????+1)−4(????−2)²
    =3????(3????+1)+1(3????+1)−4(????−2)²
    =9????²+3????+1(3????+1)−4(????−2)²
    =9????²+3????+3????+1−4(????−2)²
    =9????²+6????+1−4(????−2)²
    =9????²+6????+1−4(????−2)(????−2)
    =9????²+6????+1−4(????(????−2)−2(????−2)
    =9????²+6????+1−4(????²−2????−2(????−2)
    =9????²+6????+1−4(????²−2????−2????+4)
    =9????²+6????+1−4(????²−4????+4)
    =9????²+6????+1−4????²+16????−16
    =9????²+6????−15−4????²+16????
    =5????²+6????−15+16????
    =5????²+22????−15
    e)9(2x+3)²-4(x+1)²
    =9(2????+3)(2????+3)−4(????+1)²
    =9(4????²+12????+9)−4(????+1)²
    =36????²+108????+81−4(????+1)²
    =36????²+108????+81−4(????²+????+????+1)
    =32????²+108????+77−8????
    =32????²+100????+77
    f)4b^2c-(b^2+c^2-a^2)^2
    =4????2????−1(−????2+????2+????2)2
    =4????2????−1(−????2+????2+????2)(−????2+????2+????2)
    =4????2????−1((−????2+????2+????2)(−????2)+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
    =4????2????−1(−(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
    =4????2????−1(−(−????2⋅????2+????2????2+????2????2)+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
    =4????2????−1(−(????2????2+????2????2−????2⋅????2)+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
    =4????2????−1(−1????2????2−1????2????2−1(−????2)⋅????2+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
    =1(−1????2????2−1????2????2−1(−????2)⋅????2+(−????2+????2+????2)⋅????2+(−????2+????2+????2)⋅????2)
     

  2. khanhngantoan
    khanhngantoan
    7 Tháng Mười Hai, 2022 at 2:01 sáng
    Reply
    Giải đáp:
     Dưới nha.
    Lời giải và giải thích chi tiết:
    a, 4x²-12x+9 = (2x)²-2.(2x).3+3² = (2x-3)²
    b, 4x²+4x+1 = (2x)²+2.(2x).3+1² = (2x+1)²
    c, 1+12x+36x² = 1²+2.1.6+6² = (1+6)²
    d, (3x+1)²-4(x+1)² = [(3x)²+2.(3x).1+1²]-4(x²+2.x.1+1²)
                                  = (9x²+6x+1)-4(x²+2x+1)
                                  = (9x²+6x+1)-4x²-8x-4
                                  = 5x²-2x-3
    e, 9(2x+3)²-4(x+1)² = 9(4x²+12x+9)-4(x²+2x+1)
                                    = 36x²+108x+81-4x²-8x-4
                                    = 32x²+100x+77
    f, 4b²c-(b²+c²-a²)² = 4b²c-$b^{4}$+$c^{4}$+$a^{4}$+2bc-2ba-2ca
                                 

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222-9+11+12:2*14+14 = ? ( )

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