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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: b, (√3 – √2)^2 ; (3√2-1)(3√2+1) ; (√6+2)(√3-√2)

Toán Lớp 8: b, (√3 – √2)^2 ; (3√2-1)(3√2+1) ; (√6+2)(√3-√2)

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    b, 
    $(\sqrt{3}-\sqrt{2})^2$
    $=3-2\sqrt{6}+2$
    $=5-2\sqrt{6}$
    ———————–
    $(3\sqrt{2}-1)(3\sqrt{2}+1)$
    $=18-1$
    $=17$
    ———————–
    $(\sqrt{6}+2)(\sqrt{3}-\sqrt{2})$
    $=\sqrt{2}(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})$
    $=\sqrt{2}(3-2)$
    $=\sqrt{2}.1$
    $=\sqrt{2}$
     

  2. b)
    (\sqrt{3} – \sqrt{2})^2
    = \sqrt{3}^2 – 2\sqrt{3} . \sqrt{2} + \sqrt{2}^2
    = 5 – 2\sqrt{6}
    (3\sqrt{2} – 1)(3\sqrt{2} + 1)
    = (3\sqrt{2})^2 – 1
    = 18 – 1
    = 17
    (\sqrt{6} + 2)(\sqrt{3} – \sqrt{2})
    = \sqrt{6} . (\sqrt{3} – \sqrt{2}) + 2 . (\sqrt{3} – \sqrt{2})
    = \sqrt{18} – \sqrt{12} + 2\sqrt{3} – 2\sqrt{2}
    = 3\sqrt{2} – 2\sqrt{3} + 2\sqrt{3} – 2\sqrt{2}
    = \sqrt{2}

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222-9+11+12:2*14+14 = ? ( )