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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a, (x -2y)(x^2y^2 – xy + 2y) b, (1/2xy -1).(x^3 -2x -6)

Home/ Toán Lớp 8: a, (x -2y)(x^2y^2 – xy + 2y) b, (1/2xy -1).(x^3 -2x -6)

Toán Lớp 8: a, (x -2y)(x^2y^2 – xy + 2y) b, (1/2xy -1).(x^3 -2x -6)

Tháng Tư 19, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: a, (x -2y)(x^2y^2 – xy + 2y)
b, (1/2xy -1).(x^3 -2x -6)

Comments ( 2 )

  1. thanoanghha
    thanoanghha
    19 Tháng Tư, 2022 at 6:14 sáng
    Reply
    $a,$ $\left(x-2y\right)\left(x^2y^2-xy+2y\right)$
    $=xx^2y^2+x\left(-xy\right)+x\cdot \:2y-2yx^2y^2-2y\left(-xy\right)-2y\cdot \:2y$
    $=x^3y^2-x^2y+2xy-2y^3x^2+2xy^2-4y^2$
    $=y\left(x^3y-x^2+2x-2x^2y^2+2xy-4y\right)$
    $=y\left(x^2y-x+2\right)\left(x-2y\right)$
    $b,$ $\left(\dfrac{1}{2xy\:-1}\right)\cdot \left(x^3\:-2x\:-6\right)$
    $=\dfrac{1}{2xy-1}\left(x^3-2x-6\right)$
    $=\dfrac{1\cdot \left(x^3-2x-6\right)}{2xy-1}$
    $=\dfrac{x^3-2x-6}{2xy-1}$

  2. chauhoangmy98
    chauhoangmy98
    19 Tháng Tư, 2022 at 6:14 sáng
    Reply
    a) Ta có: (x -2y )(x2y2 – xy + 2y)
    = x(x2y2 – xy + 2y) – 2y( x2y2 – xy + 2y)
    = x3y2 – x2y + 2xy – 2x2y4 + 2xy2 – 4y2
    b) Ta có: (1/2xy -1). x3 -2x -6)
    = 1/2xy.(x3 -2x -6) – (x3 -2x -6)
    = 1/2x4y – x2y – 3xy – x3 + 2x + 6.
     

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222-9+11+12:2*14+14 = ? ( )

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