Toán Lớp 8: 5y/x-2 : 8xy/x^2-4x+4
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Toán Lớp 8: 5y/x-2 : 8xy/x^2-4x+4
giải giúp mk vs
Comments ( 2 )
$#Mai Phương$
$\dfrac{5y}{x-2}: \dfrac{8xy}{x^2-4x+4}$
$= \dfrac{5y}{x-2}: \dfrac{8xy}{(x-2)^2}$
$= \dfrac{5y}{x-2}. \dfrac{(x-2)^2}{8xy}$
$= \dfrac{5(x-2)}{8x}$
$\frac{5y}{x-2}$ : $\frac{8xy}{(x-2)^2}$
= $\frac{5y}{x-2}$ x $\frac{(x-2)^2}{8y}$
= $\frac{5(x-2)}{8x}$
=$\frac{5x-10}{8x}$
Vậy ……….