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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 3A. Phân tích đa thức thành nhân tử a) $x^{2}-5x+6$ b) $3x^{2}+9x-30$ c) $3x^{2}-5x-2$ d) $x^{3}-7x-6$ e) $x^{4}+2x^{3}+6x-9$ f) $x^{2}

Toán Lớp 8: 3A. Phân tích đa thức thành nhân tử
a) $x^{2}-5x+6$
b) $3x^{2}+9x-30$
c) $3x^{2}-5x-2$
d) $x^{3}-7x-6$
e) $x^{4}+2x^{3}+6x-9$
f) $x^{2}-7xy+10y^{2}$


Comments ( 2 )

  1. a)x^2-5x+6
    =x^2-2x-3x+6
    =(x^2-2x)-(3x-6)
    =x(x-2)-3(x-2)
    =(x-3)(x-2)
    __
    b)3x^2+9x-30
    =3(x^2+3x-10)
    =3(x^2+5x-2x-10)
    =3[(x^2+5x)-(2x+10)]
    =3[x(x+5)-2(x+5)]
    =3(x-2)(x+5)
    __
    c)3x^2-5x-2
    =3x^2+x-6x-2
    =(3x^2+x)-(6x+2)
    =x(3x+1)-2(3x+1)
    =(3x+1)(x-2)
    __
    d)x^3-7x-6
    =x^3+3x^2-3x^2+2x-9x-6
    =(x^3+3x^2+2x)-(3x^2+9x+6)
    =x(x^2+3x+2)-3(x^2+3x+2)
    =(x^2+3x+2)(x-3)
    =(x^2+x+2x+2)(x-3)
    =[(x^2+x)+(2x+2)](x-3)
    =[x(x+1)+2(x+1)](x-3)
    =(x+1)(x+2)(x-3)
    e)x^4+2x^3+6x-9
    =x^4+3x^3-x^3+3x^2-3x^2+9x-3x-9
    =(x^4+3x^3+3x^2+9x)-(x^3+3x^2+3x+9)
    =x(x^3+3x^2+3x+9)-(x^3+3x^2+3x+9)
    =(x^3+3x^2+3x+9)(x-1)
    =[(x^3+3x^2)+(3x+9)](x-1)
    =[x^2(x+3)+3(x+3)](x-1)
    =(x^2+3)(x+3)(x-1)
    f)x^2-7xy+10y^2
    =x^2-2x-5x+10y^2
    =(x^2-2xy)-(5xy-10y^2)
    =x(x-2y)-5y(x-2y)
    =(x-5y)(x-2y)

  2. Giải đáp + Lời giải và giải thích chi tiết:
     Bài 3:
    a, x^2 – 5x + 6
    = x^2 – 2x – 3x + 6
    = x(x – 2) – 3(x – 2)
    = (x – 3)(x – 2)
    b, 3x^2 + 9x – 30
    = 3(x^2 + 3x – 10)
    = 3(x^2 + 5x – 2x – 10)
    = 3[ x(x + 5) – 2(x + 5)]
    = 3(x – 2)(x + 5)
    c, 3x^2 – 5x – 2
    = 3x^2 + x – 6x – 2
    = x(3x + 1) – 2(3x + 1)
    = (x – 2)(3x + 1)
    d, x^3 – 7x – 6
    = x^3 + 3x^2 + 2x – 3x^2 – 9x – 6
    = (x^3 + 3x^2 + 2x) – (3x^2 + 9x + 6)
    = x(x^2 + 3x + 2) – 3(x^2 + 3x + 2)
    = (x – 3)(x^2 + 3x + 2)
    = (x – 3)(x^2 + 2x + x + 2)
    = (x – 3)[ x(x + 2) + (x + 2)]
    = (x – 3)(x + 1)(x + 2)
    e, x^4 + 2x^3 + 6x – 9
    = x^4 + 3x^3 + 3x^2 + 9x – x^3 – 3x^2 – 3x – 9
    = (x^4 + 3x^3 + 3x^2 + 9x) – (x^3 +3x^2 + 3x + 9)
    = x(x^3 + 3x^2 + 3x + 9) – (x^3 + 3x^2 + 3x + 9)
    = (x – 1)(x^3 + 3x^2 + 3x + 9)
    = (x – 1)[ x^2(x + 3) + 3(x + 3)]
    = (x – 1)(x^2 + 3)(x + 3)
    f, x^2 – 7xy + 10y^2
    = x^2 – 2xy – 5xy + 10y^2
    = x(x – 2y) – 5y(x – 2y)
    = (x – 5y)(x – 2y)
     

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222-9+11+12:2*14+14 = ? ( )