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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: x+3 / x – x / x – 3 – 9 / 3x – x^2

Toán Lớp 8: x+3 / x – x / x – 3 – 9 / 3x – x^2

Comments ( 2 )

  1. Giải đáp:
    $\dfrac{x+3}{x}-\dfrac{x}{x-3}-\dfrac{9}{3x-x²}$
    $= \dfrac{(x+3).(x-3)}{x.(x-3)}-\dfrac{x.x}{x.(x-3)}+\dfrac{9}{x.(x-3)}$
    $= \dfrac{x²-9-x²+9}{(x+3).(x-3)}$
    $=0$
     

  2. Giải đáp : 0
    \frac{x + 3}{x} – \frac{x}{x – 3} – \frac{9}{3x – x^2} ( ĐKXĐ : x \ne 0 ; 3 )
    = \frac{(x+3)(x – 3)}{x(x-3)} – \frac{x^2}{x(x – 3)} – \frac{9}{x(3 – x)}
    = \frac{(x+3)(x -3) – x^2 + 9}{x(x – 3)}
    = \frac{x^2 – 9 – x^2 + 9}{x(x – 3)}
    = \frac{0}{x(x – 3)} = 0

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222-9+11+12:2*14+14 = ? ( )