Toán Lớp 8: ???? = (3 + 1)(3 ^2 + 1)(3 ^4 + 1)(3^8 + 1)(3 ^16 + 1) và ???? = 3^32 − 1 giúp cái

Question

Toán Lớp 8:  ???? = (3 + 1)(3 ^2 + 1)(3 ^4 + 1)(3^8 + 1)(3 ^16 + 1) và ???? = 3^32 − 1 giúp cái

ngocle44 · Answer

#tnvt A=(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) 2A=2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) 2A=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) 2A=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) 2A=(3^4-1)(3^4+1)(3^8+1)(3^16+1) 2A=(3^8-1)(3^8+1)(3^16+1) 2A=(3^16-1)(3^16+1) 2A=3^32-1 =>A= frac{3^32-1}{2} Mà frac{3^32-1}{2}<3^32-1 =>(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)<3^32-1 Hay A

kimoanh34 · Answer

Giải đáp+Lời giải và giải thích chi tiết: color{orange}{ text{Bạn tham khảo~}} A=(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) =>2A=2.(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) =2.4(3^2+1)(3^4+1)(3^8+1)(3^16+1) =8(3^2+1)(3^4+1)(3^8+1)(3^16+1) =(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1) =(3^4-1)(3^4+1)(3^8+1)(3^16+1) =(3^8-1)(3^8+1)(3^16+1) =(3^16-1)(3^16+1) =3^32-1 =>A={3^32-1}/2 Vì {3^32-1}/2<3^32-1 =>A