Toán Lớp 8: (x-2)(x+2)(x mũ2+4)-(x mũ2-4)mũ 2

Question

Toán Lớp 8:  (x-2)(x+2)(x mũ2+4)-(x mũ2-4)mũ 2

chauhoangmy98 · Answer

Giải đáp+Lời giải và giải thích chi tiết:    (x - 2)(x + 2)(x&sup2; + 4) - (x&sup2; - 4)&sup2;   = (x&sup2; - 4)(x&sup2; + 4) - (x&sup2; - 4)&sup2;   = (x&sup2; - 4)(x&sup2; + 4 - x&sup2; + 4)   = 8(x&sup2; - 4)   = 8x&sup2; - 32

huongtructram · Answer

(x-2)(x+2)(2$x^{2}$+4)- (2$x^{2}$-4)          =     (    x     &sup2;     &minus;    4    )      (    x     &sup2;     +    4    )     &minus;     (    x     &sup2;     &minus;    4    )      &sup2;                  =     (    x     &sup2;     &minus;    4    )      (    x     &sup2;     +    4    &minus;    x     &sup2;     +    4    )                  =    8     (    x     &sup2;     &minus;    4    )                  =    8    x     &sup2;     &minus;    32