Toán Lớp 8: (x^2+1).(x-2)+x^2=4 mn giúp mình với
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: (x^2+1).(x-2)+x^2=4 mn giúp mình với
Comments ( 2 )
$⇔x^3-2x^2+x-2+x^2-4=0$
$⇔x^3-x^2+x-6=0$
$⇔x^3-2x^2+x^2-2x+3x-6=0$
$⇔x^2(x-2)+x(x-2)+3(x-2)=0$
$⇔(x^2+x+3)(x-2)=0$
$⇔x^2+x+3=0$ hoặc $x-2=0$
$+,x^2+x+3=0$
$x=2$
Vậy S={2}