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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 16) C=2a-1/3a-1 + 5-a/3a+1 biet 10a^2+5a=3 va 9a^2-1 khac 0 Moi nguoi giup minh voi

Toán Lớp 8: 16) C=2a-1/3a-1 + 5-a/3a+1 biet 10a^2+5a=3 va 9a^2-1 khac 0
Moi nguoi giup minh voi

Comments ( 2 )

  1. C=(2a-1)/(3a-1)+(5-a)/(3a+1)
    =((2a-1)(3a+1)+(5-a)(3a-1))/(9a^2-1)
    =(6a^2-a-1-3a^2+16a-5)/(9a^2-1)
    =(3a^2+15a-6)/(9a^2-1)
    =(3(a^2+5a-2))/(9a^2-1)
    Mặt khác : 10a^2+5a=3
    <=> 10a^2+5a-3=0
    <=> a^2+5a-2+9a^2-1=0
    <=> a^2+5a-2=1-9a^2
    to C=(3(1-9a^2))/(9a^2-1)=-3
    Vậy C=-3 khi 10a^2+5a=3 và 9a^2-1 ne 0
     

  2. C=(2a-1)/(3a-1)+(5-a)/(3a+1) (x\ne+-1/3)
    C=((2a-1)(3a+1)+(5-a)(3a-1))/((3a-1)(3a+1))
    C=(6a^2+2a-3a-1+15a-5-3a^2+a)/((3a-1)(3a+1))
    C=(3a^2+15a-6)/((3a-1)(3a+1))
    C=(3(a^2+5a-2))/(9a^2-1)
    Có: 10a^2+5a=3
    <=> a^2+5a-2=1-9a^2
    -> C=(3(1-9a^2))/(9a^2-1)=-3
    Vậy C=-3 khi 10a^2+5a=3; 9a^2-1\ne0

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222-9+11+12:2*14+14 = ? ( )

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