Toán Lớp 8: 16x^2-(x+1)^2=0
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Toán Lớp 8: 16x^2-(x+1)^2=0
helppppppppppppppppppppppppppppp
Comments ( 2 )
16{x^2} – {(x + 1)^2} = 0\\
\Leftrightarrow {\left( {4x} \right)^2} – {(x + 1)^2} = 0\\
\Leftrightarrow \left( {4x – x – 1} \right)\left( {4x + x + 1} \right) = 0\\
\Leftrightarrow \left( {3x – 1} \right)\left( {5x + 1} \right) = 0\\
\Leftrightarrow \left[ \begin{array}{l}
3x – 1 = 0\\
5x + 1 = 0
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = \frac{1}{3}\\
x = \frac{{ – 1}}{5}
\end{array} \right.
\end{array}\]