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Toán Lớp 8: 15/ x^2 – 2022x + 2021 16/ 4x(x + 1)^2 – 5x^2 (x + 1) – 4(x+1) 17/ (x + 2)( x + 3)( x + 4)( x + 5)-24 18/ x^4 + 4

Home/ Toán Lớp 8: 15*/ x^2 – 2022x + 2021 16*/ 4x(x + 1)^2 – 5x^2 (x + 1) – 4(x+1) 17*/ (x + 2)( x + 3)( x + 4)( x + 5)-24 18*/ x^4 + 4

Toán Lớp 8: 15/ x^2 – 2022x + 2021 16/ 4x(x + 1)^2 – 5x^2 (x + 1) – 4(x+1) 17/ (x + 2)( x + 3)( x + 4)( x + 5)-24 18/ x^4 + 4

Hồng Tháng Mười Hai 28, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: 15*/ x^2 – 2022x + 2021
16*/ 4x(x + 1)^2 – 5x^2 (x + 1) – 4(x+1)
17*/ (x + 2)( x + 3)( x + 4)( x + 5)-24
18*/ x^4 + 4

Comments ( 1 )

ngoclankhue
28 Tháng Mười Hai, 2022 at 4:11 chiều

Reply

$15$

$=x^2-x-2021x+2021$

$=x(x-1)-2021(x-1)$

$=(x-1)(x-2021)$

$16$

$=(x+1)(4x(x+1)-5x^2-4)$

$=(x+1)(-x^2+4x-4)$

$=-(x+1)(x^2-4x+4)$

$=-(x+1)(x-2)^2$

$17$

$=[(x+2)(x+5)][(x+3)(x+4)]-24$

$=(x^2 + 7x +10)(x^2 + 7x +12)-24$

$Đặt x^2+7x+11=a$

$⇔=(a-1)(a+1)-24$

$=a^2-25$

$(a+5)(a-5)$

$⇔=(x^2+7x+16)(x^2+7x +6)$

$=(x^2+7x+16)(x^2++x+6x +6)$

$(x^2+7x +6)[(x+1)x+6(x+1)]$

$(x^2+7x +6)(x+1)(x+6)$

$18$

$=x4+2x^3+2x^2−2x^3−4x^2−4x+2x^2+4x+4$

$=(x^2+2x+2).x^2 – 2x(x^2+2x+2)+2(x^2+2x+2)$

$(x^2-2x+2)(x^2+2x+2)$

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