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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1)Thực hiện phép tính : a) x(5 – 2x) + 2x(x – 1) b) (20x^4y – 25x^2y^2 – 3x^2y) : 5x^2y 2)Phân

Toán Lớp 8: 1)Thực hiện phép tính : a) x(5 – 2x) + 2x(x – 1)
b) (20x^4y – 25x^2y^2 – 3x^2y) : 5x^2y
2)Phân tích đa thức thành nhân tử : a) x^2 – xy + x – y ; b)2x^2 + 4x + 2 – 2y^2

Comments ( 2 )

  1. a)
    x.(5-2x)+2x.(x-1)
    =x.5-x.2x+2x.x-2x.1
    =5x-2x^2+2x^2-2x
    =(5x-2x)+(2x^2-2x^2)
    =3x
    $\\$
    b)
    (20x^4y-25x^2y^2-3x^2y):5x^2y
    =(20x^4y:5x^2y)-(25x^2y^2:5x^2y)-(3x^2y:5x^2y)
    =4x^2-5y-\frac{3}{5}
    $\\$
    —————————————–
    $\\$
    a)
    x^2-xy+x-y
    =(x^2-xy)+(x-y)
    =x.(x-y)+(x-y)
    =(x-y).(x+1)
    => Nhóm hạng tử.
    => Đặt nhân tử chung.
    $\\$
    b)
    2x^2+4x+2-2y^2
    =2.(x^2+2x+1-y^2)
    =2.[(x^2+2x+1)-y^2]
    =2.[(x+1)^2-y^2]
    =2.(x+1-y).(x+1+y)
    => Đặt nhân tử chung
    => Nhóm hạng tử.
    => Dùng hằng đằng thức: 
    @(a+b)^2=a^2+2ab+b^2
    @a^2-b^2=(a+b).(a-b)
     

  2. Giải đáp:
    $a)$ 
    $1) x.(5-2x)+2x.(x-1)$
    $= 5x-2x²+2x²-2x$
    $= (2x²-2x²)+(5x-2x)$
    $= 3x$
    $2) (20x^4y-25x²y²-3x²y):5x²y$
    $= (20x^4y:5x²y)-(25x²y²:5x²y)-(3x²y:5x²y)$
    $= 4x²-5y-\dfrac{3}{5}$
    $b)$
    $1) x²-xy+x-y$
    $= (x²-xy)+(x-y)$
    $= x.(x-y)+1.(x-y)$
    $=(x-y).(x+1)$
    $2) 2x²+4x+2-2y²$
    $= 2.(x²+2x+1-y²)$
    $= 2.[(x+1)²-y²]$
    $= 2.(x+1-y).(x+1+y)$

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222-9+11+12:2*14+14 = ? ( )